Three brothers divide 17 candy bars. The oldest child gets 1/2, the middle child 1/3, and the youngest child 1/9. So that they do not have to cut any bars, Mom provides an extra one. The oldest child then takes 9 candy bars, the middle child 6, and the youngest 2, and they return the extra one. Which child received more than his fair share? answer Coffey, M. (Ed.). (2011). January "Calendar" Problems. MATHEMATICS TEACHER , 104 (5), 368-369.
0 Comments
|
Math Problem of the DayJust like any good sport, mathematics needs to be practiced everyday to excel at it. Archives
September 2013
Categories
All
Website created
November 13, 2009 by Mr. Kruczinski
Contact Mr. Kruczinski by e-mail: [email protected] You can follow me on TWITTER at @MrKruczinski All files created by Mr. Kruczinski are not copyrighted. The problems, comics, and images are copyrighted by their respective creators. Remember to make a difference--SUBTRACT!!! |
Photos from lydia_shiningbrightly, peasap, visualpanic, Manu_H, Mark Sadowski, stuartpilbrow, stuartpilbrow, rkramer62, Nils Geylen, aussiegall, Tracy O, DeaPeaJay, m.r.e., Joe Shlabotnik, geishaboy500, eleanor ryan, Neal., milos milosevic, Johan Larsson, PinkMoose, ralphunden, Conspirator, MikeBehnken, fdecomite, William Hook, feeliz, Loren Javier, Pink Sherbet Photography, aussiegall